1、项目需求：在a程序中点击打开b程序
2、代码实现：

index.html：
//按钮点击事件
machineBtn.click(()=>{
		let exePath;
		//exePath.config文件里面是b程序的路径
		fs.readFile('exePath.config', 'utf-8', function(err, data) {
			exePath = data;
			ipcRenderer.send('open-child',exePath);
		})		
})

main.js：
let spawn = [];
ipcMain.on('open-child',(e,msg)=>{
	var childSpawn = childProcess.spawn(msg);
	spawn[spawn.length] = childSpawn;
})

补充：关闭程序

index.html:
ipcRenderer.send('close-child',exePath);

main.js:
ipcMain.on('close-child',(e,msg)=>{
	console.log("close",msg)
	for(var i = 0;i<spawn.length;i++){
		spawn[i].kill();
	}
	spawn = [];
})